Math, asked by GENIUSx100, 3 months ago

Ramesh places
a mirror on level
ground to
determine the height of a pole (with traffic light fired on it). He stands at a
certain distance so that he can see the top of the pole reflected from the mirror.
Ramesh’s eye level is 1.5 m above the ground. The distance of Ramesh and the
pole from the mirror are 1.8 m and 6 m respectively.
On the basis of the above information, answer any four of the following
questions:

(i) Which criterion of similarity is applicable to similar triangles?
(a) SSA
(b) ASA
(c) SSS
(d) AA

(ii) What is the height of the pole?
(a) 6 metres
(b) 8 metres
(c) 5 metres
(d) 4 metres

(iii) If angle of incidence is i , which of the following is correct relation?
(a) tan i=5/6
(b) tan i= 6/5
(c) tan i= 3/5
(d) tan i= 5/3
(iv) Now Ramesh move behind such that distance between pole and Ramesh is
13 meters. He places mirror between him and pole to see the reflection of light
in right position. What is the distance between mirror and Ramesh ?
(a) 7 metres
(b) 3 metres
(c) 5 metres
(d) 4 metres

(v) What is the distance between mirror and pole?
(a) 9 metres
(b) 8 metres
(c) 12 metres
(d) 10 metres

pls answer correct and fast its urgent

Answers

Answered by amitnrw
7

Given : Ramesh’s eye level is 1.5 m above the ground. The distance of Ramesh and the

pole from the mirror are 1.8 m and 6 m respectively.

To Find : (i) Which criterion of similarity is applicable to similar triangles?

(a) SSA

(b) ASA

(c) SSS

(d) AA

(ii) What is the height of the pole?

(a) 6 metres

(b) 8 metres

(c) 5 metres

(d) 4 metres

(iii) If angle of incidence is i , which of the following is correct relation?

(a) tan i=5/6

(b) tan i= 6/5

(c) tan i= 3/5

(d) tan i= 5/3

Solution:

criterion of similarity is applicable to similar triangles AA

as common angle and right angles are common

height of the pole = h

=> h/1.5 = 6/1.8

=> h = 9/1.8

=> h = 5 m

height of the pole = 5 m

Tan i  = 5/6

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Answered by anchals04307
3

Answer:

i- AA

ii- 5 meter

iii - 6/5

iv - 3 meter

v- 10 meter

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