Question

Ramesh rides his scooter with 20m/s and applies brake and come to stop in 10s find the acceleration and distance covered before comes to stop
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Answer 1

Answer:

a = -2m/s²

S = 100 m

Explanation:

u = 20 m/s

v = 0 m/s

t = 10 s

v = u + at

S = ut + 1/2 at²

Substitute them in this formula. You will get it.

Answer 2

Explanation:

Given:-

u=20m/s${}^{2}$

v=0

t=10s

Solution:-

Let

acceleration=a

distance=s

Formula used:-

${:}\longrightarrow$${\boxed{v=u+at}}$

${:}\longrightarrow$${\boxed{s=ut+{\frac{1}{2}}at{}^{2}}}$

now,

Using first formula

${:}\longrightarrow$$v=u+at$

${:}\longrightarrow$$0=20+a×10$

${:}\longrightarrow$$10a=-20$

${:}\longrightarrow$$a={\frac{-20}{10}}$

${:}\longrightarrow$${\underline{\boxed{\bf{a=-2m/s{}^{2}}}}}$

using second formula

${:}\longrightarrow$$s=ut+{\frac{1}{2}}at{}^{2}$

${:}\longrightarrow$$s=20×10+{\frac{1}{{\cancel{2}}}}×({\cancel{-2}})×{10}^{2}$

${:}\longrightarrow$$200+(-1×100)$

${:}\longrightarrow$$200+(-100)$

${:}\longrightarrow$$200-100$

${:}\longrightarrow$${\underline{\boxed{\bf{s=100m}}}}$