Math, asked by eshwarappadeshwarapp, 8 months ago

ramesh started work in 2000 at annual salary of ₹1000 and received an increment of₹2000 each year in which year did his incom
e reach₹20000​

Answers

Answered by anantmalviya4336
29

Answer:

In year, 2010 in 5 th month Ramesh income reach ₹20000

Step-by-step explanation:

Hope,it will help you !

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Answered by ZzyetozWolFF
33

Answer:

On 10th year.

Step-by-step explanation:

Salary on 2001 = 1000 + 2000

=> 3000

Salary in 2002 = 2000 + 2000

=> 4000

Salary in 2003 = 4000 + 2000

=> 6000

We will use Arithmetic progression here as we can see that there is series followed. ie. 3000, 4000, 6000....

a(n) = a + (n -1) d

 \implies  \sf \: 20000 = 1000 + (n - 1) \times 2000

\implies  \sf \: 20000 = 2000n + ( - 1000)

\implies  \sf \: 20000 = 2000n - 1000

Flip it!

\implies  \sf \: 2000n - 1000 = 20000

Add 1000 to both sides:-

\implies  \sf \: 2000n - 1000 + 1000 = 2000 + 1000

\implies  \sf \: 200n = 21000

Divide both by 2000:-

\implies  \sf \:  \dfrac{2000n}{2000}  =  \dfrac{21000}{2000}

\implies  \sf \: n =  \dfrac{21}{2}

\implies  \sf \: n = 10.5

On 10th year his salary would be Rs 2000

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