Ramesh, Suresh, Seema and Sana are four friends in a class. A maths assignment is given in the class. Ramesh solved 3/4 part of the assignment, Suresh solved 7/10 part, Seema solved 4/5 part and Sana solved 5/8 part of the assignment at the same time. Who solved least part of the assignment?
Answers
Four friends had a competition to see how far they could hop on one foot. the table given shows the distance covered by each.
Name Seema Nancy Megha Soni
Distance covered (km)
25
1
32
1
40
1
20
1
(a) How farther did Soni hop than Nancy?
(b) What is the total distance covered by Seema and Megha?
(c) Who walked farther, Nancy or Megha?
Medium
Solution
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(a) Distance covered by Soni =
20
1
km
Distance covered by Nancy =
32
1
km
∴ Difference between Soni's and Nancy's hop =
20
1
−
32
1
=
160
8−5
=
160
3
km
(b) Distance covered by Seema =
25
1
km
Distance covered by Megha =
40
1
Total distance covered by Seema and Megha =
25
1
+
40
1
=
200
8+5
=
200
13
km
(c) Distance covered by Nancy =
32
1
km=
160
5
km
distance covered by Megha =
40
1
km=
16
4
km
Comparing these numbers, we get
160
5
>
16
4
∴
32
1
>
40
1
Hence, Nancy walked further