Physics, asked by superstar4ever, 6 months ago

Ramesh takes 15 minutes to reach market from his house on this cycle. If the speed of his cycle is 4 m/s calculate the distance between his house and market?

Answers

Answered by vikramaditya4237
43

Answer:

3.6 Km

Explanation:

As the question tells,

Ramesh takes 15 minutes to reach market from his house on his cycle and the speed of the cycle is 4m/s.

So, Total distance between market and his house =

Total distance covered by Ramesh's cycle in 15 minutes with a speed of 4m/s.

i.e. 4x60m in 1 minute.(as 4m in 1 sec, so in 60 seconds, 4x60m)

=240m

So, he travels 240m in 1 minute.

So, in 15 minutes, he will travel

15x240 = 3600m = 3.6Km

So, the distance between his house and the market is 3.6Km

Answered by nirman95
15

Given:

Ramesh takes 15 minutes to reach market from his house on this cycle and the speed of his cycle is 4 m/s.

To find:

Distance between house and market ?

Calculation:

  • Distance is a scalar quantity which can be calculated by multiplying the speed with time taken.

  • 15 minutes = 15 × 60 = 900 seconds.

  • Let distance be D :

 \therefore \: D = v \times t

 \implies \: D = 4 \times 900

 \implies \: D = 3600 \: m

 \implies \: D = 3.6 \: km

So, distance between house and market is 3.6 km.

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