Ramesh takes twice as much time as mahesh and thrice as much time as suresh to complete a job. if working together, they can complete the job in 4 days, then the time taken by each of them separately to complete the work is
Answers
Let Ramesh, Mahesh and Suresh can finish the work alone in x, y and z days.
But according to question, x = 2y = 3z. that means Ramesh takes twice as much time as mahesh and thrice as much time as suresh to complete the job.
So we can write y = x/2 and z = x/3.
Now, if Ramesh takes x days to complete 1 work. So in 1 day he can do 1/x part of the work.
Similarly, Mahesh and Suresh can do 2/x and 3/x part of the work in 1 day.
So, combinedly they can do 1/x + 2/x + 3/x part of work in 1 day.
their total work in 1 day = 1/x + 2/x + 3/x = 6/x
their total work in 4 days = 24/x part of work.
Acc to ques they are finishing 1 work in 4 days that means 24/x part of work = 1.
Therefore we get the value of x = 24 i.e. Ramesh takes 24 days to complete the task, Mahesh takes 12 days to complete the task and Suresh takes 8 days to complete the task.
Answer:
Rahul takes 24 hours, Mahesh takes 12 hrs and Sachin takes 8 hours to complete the job