Question

ramesh took 2 beakers A and B containing hot water and cold water respectively in each beaker he dropped a crystal of copper sulphate after sometime what did he observe and why​

Answer 1

Explanation:

must have observed that copper sulphate(CuSO4) has diffused evenly in beaker A than in beaker B. This describes the phenomenon of diffusion. On heating, the kinetic energy of the particles increases. Thus, diffusion becomes faster. Therefore, the particles of CuSO4 must have diffused quickly in beaker A than in beaker B.

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Anushka Gupta answered this

19 helpful votes in Science, Class XII-Science

He must have observed that the crystal of copper sulphate in beaker A has diffused evenly than in beaker B. This describes the phenomenon of diffusion. On heating, diffusion becomes faster because the kinetic energy increases. So the particles of CuSO4(copper sulphate) must have diffused with the particles of hot water quickly than in the cold water.

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