Question

Ramesh Travels 760 km partly by train and partly by train he takes 8 hours to travel 160 km by train and raised by car if he takes 12 minutes more if he travels 240 km by train and Rekha find the speed of train and car

Answer 1

Let the speed of train = x km/hr and
speed of car= by km/hr
Case 1
Distance travelled by train = 160 km
Distance travelled by car = 760-160 =
600km
Time taken by train = 160/x hr
Time taken by car =600/y hr
Total time taken = 160/x+600/y hr160/
X+600/y = 8 Equation 1
Case 2
Distance travelled by train = 240 Km
Distance travelled by car = 760-240 =
520 km
Time taken by train = 240/x hr
Time taken by car = 520/y hr
Total time taken = 240/x+520/y hr 240/
x+520/y = 8+12/60 (12
minutes=12/60 hr)
240/x+520/y = 41/5

Equation 2
Multiply equation 1 by 3 and equation 2
by 2 and subtract equation 2 from
equation 1
1800/y-1040/y = 24-82/5
760/y = 38/5
y =(760X5)/38
= 100
Putting y = 100 in equation 1
160/x+600/100 = 8
X = 80
Speed of Car = 100 km/hr
Speed of train = 80 km/hr

Answer 2

Answer:

Speed of train=80km/ hr

Speed of car =60km/hr

Step-by-step explanation:

Speed of train=x km/hr

Speed of car =y km/hr

160/x+600/y=8

240/x+520/y=8(12/60)

1/x=a 1/y=b

160a+600b=8

20a+75b=1-------(1)

240a+520b=492/60

1200a+2600b=41------(2)

(1)=>b=1-20a/75--------(3)

(3) in (2)

1200a+2600(1-20a/75)=41

1200a+(104-2080a/3)=41

3600a+104b-2080a=41

1520a=19

a=1/80

b=1-20(1/80)/75

b=(4-1/4)/75

b=3/4*75

b=1/60

X=80km/h

Y=60km/h