Question

Ramesh wants to build a small fence in his backyard. The garden is in the shape of right triangle. If one leg is 2 m and other leg is 1 m. He goes to the store for purchasing fencing. The store sells fencing in tenth of a metre. A. Find the perimeter of Ramesh's garden. B. What length of fencing should Ramesh purchase if store only sells fencing in tenth of a metre.​

Answer 1

Answer:

Given-

1st leg of garden = 2m= base

2nd leg of garden = 1m=perpendicular

1m =10th decimeter

so , 1m =10 deci M

and 2m = 20 deci M

3rd side of ∆

h= √(p^2 +b^2)

h= √(1^2 + 2^2)

h= 1+2

h= 3m =30 deci M

Now ,perimeter of right ∆

= sum of all sides

= 1+2+3 M

=6 M

now length of fencing Ramesh should buy

= 10 + 20 + 30 deci M

= 60 deci M, tenth of meter.

Mark it as BRAINLIEST!!!!

Answer 2

Answer:

3+√5 m, 3+√5 dm

Step-by-step explanation:

h=√(1^2+2^2) = √5 so p= h+b+p =3+√5 m

2nd ans 3+√5/10 = 3+√5 dm ( decimeter)