Ramesh was driving a car at 20m/s. He applied brakes which generated force equal to -500N. Find the distance after which car will stop if its weight is 100kg.
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Answer:
120 m
Explanation:
we know that, F=m(v-u)/t
putting the values,
-500= 100*(0-20)/t
-500/-2000=1/t
t=2000/500
t=4s
now,a=(v-u)/t
putting the values,
a=0-20/4
a=-5m/s^2
we know by the first equation of motion that,
s=ut+1/2at^2
s=20*4+1/2*5*4^2
s=80+40
s=120m
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