Math, asked by iammad03, 9 months ago

Ramesh worked for 2/4 of an hour. Meeta works for 2/3 of an hour. How much they work altogether...​

Answers

Answered by riya8674
1

Answer:

ramesh worked for 2/4×60=30mins

meeta worked for 2/3×60=40mins

together they worked for

1/30+1/40=7/120

=120/7mins

or

2/7 of an hour(120/7×60)

hope it helps you

MARK it as BRAINLIEST:)

Answered by Anonymous
3

➣ AnSwer :-

Way :-1

 \longrightarrow \sf \: \frac{2}{4}  +  \frac{2}{3}  \\

LCM of 4 and 3 is 12.

 \longrightarrow \sf \: \frac{2 \times 3}{4 \times 3}  +  \frac{2 \times 4}{3 \times 4}  =  \frac{6}{12}  +  \frac{8}{12}  \\

 \longrightarrow \sf \: \frac{6 + 8}{12}  =  \cancel \frac{14}{12} =  \frac{7}{6}  \\

____________________________

Way :-2

1 hour = 60 minutes

So,

Ramesh working time

 \longrightarrow \sf \: \frac{2}{4}  \times 60 =  \frac{2}{4}  \times  \frac{60}{1}  \\

 \longrightarrow \sf \cancel \frac{120}{4} =  \frac{30}{1}  = 30 \\

Ramesh works for 30 minutes...

Meera working time

 \longrightarrow \sf \: \frac{2}{3}  \times 60 =  \frac{2}{3}  \times  \frac{60}{1}  \\

 \longrightarrow \sf \cancel  \frac{120}{3} =  \frac{40}{1}  = 40  \\

Meera works for 40 minutes...

Total time they work altogether :-

30+40 minutes

= 70 minutes

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