Question

Ramiya is using the quadratic formula to solve a quadratic equation. Her equation is x = StartFraction negative 3 plus or minus StartRoot 3 squared minus 4(1)(2) EndRoot Over 2(1) EndFraction after substituting the values of a, b, and c into the formula.

Which is Ramiya’s quadratic equation?

Quadratic formula: x = StartFraction negative b plus or minus StartRoot b squared minus 4 a c EndRoot Over 2 a EndFractionLaTeX: 0=2x^2+3x+1 0 = 2 x 2 + 3 x + 1

LaTeX: 0=2x^2-3x+1 0 = 2 x 2 − 3 x + 1

LaTeX: 0=x^2-3x+2 0 = x 2 − 3 x + 2

LaTeX: 0=x^2+3x+2

Answer 1

The quadratic equation is x² + 3x + 2 = 0.

Step-by-step explanation:

If a quadratic equation is ax² + bx + c = 0, the using the quadratic equation the solutions for x will be given by

$x = \frac{- b \pm \sqrt{b^{2} - 4ac}}{2a}$. .......... (1)

Now, in our case the solution for x are

$x = \frac{- 3 \pm \sqrt{3^{2} - 4(1)(2)}}{2(1)}$ ............ (2)

So, comparing equations (1) and (2) we get, a = 1, b = 3 and c = 2.

Therefore, the quadratic equation is x² + 3x + 2 = 0. (answer)

Answer 2

Answer:

The correct answer is A.

Step-by-step explanation:

It's on Edgenuity.