Ramkali saved 5 in the first week of a year and then increased her weekly savings by 1.75. If in the nth week, her weekly savings become 20.75, find n.
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Answer:
Step-by-step explanation:
The given problem forms an AP with first term=5
d=1.75
Sum=20.75
20.75=n/2(2a+(n-1)d)
20.75=n/2(10+1.75n-1.75)
41.5=10n+1.75n^2-1.75
1.75n^2+10n-43.75=0
use n=-b+Sqrt(b^2-4ac)/2a to solve
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