Ramlal sold two cars for rupees 18,000 each. on one he gained 10% and on the other he lost 10% find the net loss and loss percent
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for 1st
profit =10%of 18000
10/100× 18000 =1800 rs.
For 2nd
loss = 10% of 18000 =rs.1800
on both transactions net loss is zero.
profit =10%of 18000
10/100× 18000 =1800 rs.
For 2nd
loss = 10% of 18000 =rs.1800
on both transactions net loss is zero.
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total sp=18000+18000=36000
find the cp of 1st object which would be 180000÷11
and then calculate the 2nd object's cp which is 20000
calculate total cp which is 400000÷11
find loss=(400000÷11)-36000=4000÷11
so loss is 4000÷11
loss percentage is 400000÷11×(11×400000)=1
so loss percentage is 1%
find the cp of 1st object which would be 180000÷11
and then calculate the 2nd object's cp which is 20000
calculate total cp which is 400000÷11
find loss=(400000÷11)-36000=4000÷11
so loss is 4000÷11
loss percentage is 400000÷11×(11×400000)=1
so loss percentage is 1%
why r u take 180000÷11
in which ques
cp of 1st article=(18000×100)÷10÷100×11
sorry it is (18000×100)÷10+100
let the cost price be 100
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