Question

Ramprasad mixed 120 liters of milk with 30 liters of water. he sells 50 liters of this mixture and leaves his shop.his son then adds water to the remaining mixture to make it 150 litures.if a consumer buys 15 liters of this mixture find the amount of pure milk that he gets

Answer 1

120(pure)+30(water)=150.........it is 3x40 pure nd 3x10 water(sells 50 means 1x40 pure nd 1x10 water)
80(pure)+20(water)=100
80(pure)+(20+50)[water]=150. ....(bcoz of adding 50L to make 150L)
72.5[pure]+62.5[water]=135(15 L buys means 7.5 pure nd 7.5 water)
then, tht customer gets 7.5 L pure milk

Answer 2

Answer:

Step-by-step explanation:

120lts milk + 30lts water = 150 lts of mixture

the 50 lts which is sold will be divided in the ratio of the above mixture ratio,i.e., 120:30 (4:1)

therefore, after selling of 40 lts milk and 10 lts water

80 lts of milk and 20 lts of water is left.

now, his sons adds 50 lts water to make 150 lts mixture, now the new ratio of water and milk will be 80:70(20+50) and now the 15 lts will be divided in this ratio, i.e., 8:7

therefore the amount of pure milk is (15*8)/15 = 8