Question

Ramu and somu are en race . Ramu
is ahead of somu by 5m. Somu has.
to cross 22m to finish the race. On
seeing the lag of somu, Ramu derides
he will win for sure and reduces the
velocity by Oolm m/s. Their initial
velocity is 5 m/s and 4 m/s respectively.
What must be acceleration taken by
Somu so that he can finish the same
rare at the same time.​

Answer 1

The acceleration taken by the sonu to finish the race is 0.449 m/$s^{2}$.

Explanation:

Let v be the velocity increase taken by the Sonu to finish the race with Ramu.

We know,

                               ⇒ s = $\frac{d}{t}$

                              ⇒ t = $\frac{d}{s}$

                              ⇒ t =$\frac{22}{4}$ = 5.5 seconds

This the time taken by the Sonu to finish the race.

Time taken by Ramu,

                                 ⇒ t = $\frac{17}{5}$

Now to finish the race in same time.compete both the time with Sonu';s increased speed.

                                      ⇒ $\frac{22}{v+4} = \frac{17}{5}$

                                      ⇒ v = 2.470 m/s

Now,

          acceleration = $\frac{v}{t}$

                                                     ⇒ a = $\frac{2.470}{5.5}$

                                                  ⇒ a = 0.449 m/$s^{2}$