Ramu completes 30% of work in 7.5 days. Raju is 50% as efficient as ramu, venu is 50% as efficient as raju. Now raju and venu joined with ramu for the rest of the work then in how many days will take to complete the work?
Answers
Ramu completes 30% of work in 7.5 days
30% = 7.5 days
1% = 7.5 ÷ 30 = 0.25 days
100% = 0.25 x 100 = 25 days
Amount of work Ramu can do in a day:
1 day = 1/25 of the work
Amount of work Raju can do in a day:
Raju is 50% as efficient as Ramu
1 day = 1/25 ÷ 2 = 1/50 of the work
Amount of work Venu can do in a day:
Venu is 50% as efficient as Raju
1 day = 1/50 ÷ 2 = 1/100 of the work
Together:
1 day = 1/25 + 1/50 + 1/100 = 7/100 of the work
Amount of work left to do:
Ramu has completed 30% of the work
Amount of work left = 1 - 3/10 = 7/10
Find the number of days needed to complete the remaining work:
Number of days = 7/10 ÷ 7/100 = 10
Answer: They need 10 days to complete the remaining of the work.
Given:
Ramu,
30 % in 7.5 days
Raju is 50 % of Ramu
Venu is 50 % of Raju
Raju and venu joined with ramu to complete the work
To find:
The number of days needed to complete the work.
Solution:
If,
30% in 7.5 days
1% = 7.5 / 30
Ramu does 1 % in 0.25 days
To complete the work,
Ramu takes,
0.25 * 100 =25 days
In 1 day,
Ramu does,
1/25
Raju does,
1/25 / 2
1/50
Venu does,
1/50 / 2
1/100
If all three combine,
1/25 + 1/50 + 1/100
7/100
To find the work left,
1 - 30/100
7/10
To find the number of days all three can combine to finish the work,
Work left / Work done by all three in a day
7/10 / 7/100
10 Days
Hence, The number of days needed to complete the work is 10 days.