Math, asked by sdpbura, 10 days ago

Ramu is renting DVDs from the video store. He must choose three DVDs from a list of eight new releases and then decide in what order to watch them. How many different schedules of DVDs can he create, if he cannot watch the same movie more than once?..​

Answers

Answered by ram937gm
2

Answer:

336

Step-by-step explanation:

eight c 3 into 3 factorial

Answered by halamadrid
0

Answer:

336 ways

Given:

Ramu is renting DVDs from the video store. He must choose three DVDs from a list of eight new releases and then decide in what order to watch them.

To find:

How many different schedules of DVDs can he create, if he cannot watch the same movie more than once ?

Solution:

Through permutation:

8p3 = 8! / 5! = 8*7*6 = 336

Through combination:

8c5 = 8! / (5!3!) = 8*7*6 / 6 = 8*7 = 56

but these 3 can be arranged in 3! ways

so 56 * 3! = 336

#SPJ2

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