Question

Ramu's age is 1/6 times of his father's age. The present sum of the ages of Ramu, father and mother is 70. When Ramu's age gets doubled their sum is twice the present sum.find fathers present age

Answer 1

Answer:

Data given has some mistakes

Step-by-step explanation:

Let say Father Present age  = 6R   years

Then Ramu Present Age = (1/6) 6R  = R   Years

The present sum of the ages of Ramu, father and mother is 70.

=> Mother Age  = 70 - 6R - R

= 70 - 7R  years

When Ramu's age gets doubled

=> Ramu age = 2* R = 2R

=> Ramu's age increased by 2R - R  = R years

so Father & Mother age also increased by R year each

Hence (6R + R) + (R + R)  + (70 - 7R + R)   = 2 * 70

=> 3R = 70

=> R = 70/3

Father Present age  = 6R = 6 * 70/3  = 140 Years

Which is not Possible

as present sum of the ages of Ramu, father and mother is 70

Hence Data given has some mistakes

Found a similar question

The sum of their (father, mother and son) ages is 70. The father is 6 times as old as the son.When the sum of their ages is twice 70, the father will be twice as old as the son.How old is the Father

Let say Father Present age  = 6R   years

Then Ramu Present Age = (1/6) 6R  = R   Years

The present sum of the ages of Ramu, father and mother is 70.

=> Mother Age  = 70 - 6R - R

= 70 - 7R  years

Let say after X years the sum of their ages is twice 70

=> 3X = 70   => X = 70/3

Father Age = 6R + 70/3

Son age = R + 70/3

6R + 70/3 = 2(R + 70/3)

=> 4R = 70/3

=> R = 35/6

Father Age = 6R = 35 Years