Ramu swims in a 90m long pool he covers 180 m in 1 minutes by swimming from one end to the other and back along the same straight path find the average speed of average velocity of Ramu
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Average speed is the total distance covered by total time taken.
Here the total distance covered is 90 + 90 = 180m
So average speed = 180m/60s
= 3m/s
Average velocity is the displacement by time taken
Here displacement = 90-90 = 0
So, average velocity is 0m/s
Here the total distance covered is 90 + 90 = 180m
So average speed = 180m/60s
= 3m/s
Average velocity is the displacement by time taken
Here displacement = 90-90 = 0
So, average velocity is 0m/s
NihaGiha:
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Answered by
6
@
Average speed = distance / time
=(180/60)m/s
=3m/s
Average speed of ramu = 3 m/s
______________________
Average velocity = displacement / time
=0/60
=0
Average velocity of ramu = 0 m/s
@:-)
Average speed = distance / time
=(180/60)m/s
=3m/s
Average speed of ramu = 3 m/s
______________________
Average velocity = displacement / time
=0/60
=0
Average velocity of ramu = 0 m/s
@:-)
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