Math, asked by mahindrach30, 1 month ago

Ramus rectangular garden has length = 2x, breadth = 3y, Perimeter=26
2. By
RAJU
Raju's rectangular garden has length = 4x, breadth - 5y, perimeter 46 m
a) 36m
What is the Area of Ramu's rectangular garden
b) 48m
What is the Area of Raju's rectangular garden
b) 140m
Sum of the areas of two rectangular gardens is
b) 188m
c) 54m
a) 120m
d) 72m
c) 150m
a) 156m
d) 160m
c) 204m
d) 332m

Answers

Answered by amitnrw
2

Given : Ramus rectangular garden has length = 2x, breadth = 3y, Perimeter=26

Raju's rectangular garden has length = 4x, breadth - 5y, perimeter 46 m

To Find  : Area of Ramu's rectangular garden

Area of Raju's rectangular garden

areas of two rectangular gardens  

Solution:

Perimeter of rectangle  = 2 ( length + breadth )

Area  of rectangle = length * breadth

Ramus rectangular garden has length = 2x, breadth = 3y, Perimeter=26

=> 2 ( 2x + 3y)  = 26

=> 2x + 3y  = 13   Eq1

Raju's rectangular garden has length = 4x, breadth - 5y, perimeter 46 m

=> 2 (4x + 5y) = 46

=> 4x + 5y  = 23    Eq2

2* Eq1 - Eq2

=> y  = 3

   2x + 3(3) = 13 => x = 2

Ramus rectangular garden has length = 4, breadth = 9,  

Area = 4 x 9  = 36   m²

Raju's rectangular garden has length = 8, breadth 15

Area  = 8 x 15  = 120 m²

Area of both = 36 + 120 = 156  m²

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