Math, asked by ipshitadhyani, 9 months ago

Ramya told Krishna “12 times the date of my birth added to 31 times the month of my birth is 376”. On which date was Ramya born?

Answers

Answered by RvChaudharY50
1

Given :- Ramya told Krishna “12 times the date of my birth added to 31 times the month of my birth is 376”. On which date was Ramya born ?

Solution :-

Let us assume that, Ramaya was born on D date in the month of M . where 1 ≤ D ≤ 31 and 1 ≤ M ≤ 12 .

so,

→ 12 * D + 31 * M = 376

→ 12D = 376 - 31M

→ D = (376 - 31M)/12

putting values of M from 1 to 12 for positive integer we get,

  • M = 1 => (376 - 31)/12 = 345/12 ≠ integer .
  • M = 2 => (376 - 31*2)/12 = 314/12 ≠ integer .
  • M = 3 => (376 - 31*3)/12 = 283/12 ≠ integer .
  • M = 4 => (376 - 31*4)/12 = 252/12 = 21 = integer .
  • M = 5 => (376 - 31*5)/12 = 221/12 ≠ integer .
  • M = 6 => (376 - 31*6)/12 = 190/12 ≠ integer .
  • M = 7 => (376 - 31*7)/12 = 159/12 ≠ integer .
  • M = 8 => (376 - 31*8)/12 = 128/12 ≠ integer .
  • M = 9 => (376 - 31*9)/12 = 97/12 ≠ integer .
  • M = 10 => (376 - 31*10)/12 = 66/12 ≠ integer .
  • M = 11 => (376 - 31*11)/12 = 35/12 ≠ integer .
  • M = 12 => (376 - 31*12)/12 = 4/12 ≠ integer .

therefore,

→ Only possible value of M = 4

then,

→ D = 21

Hence, Ramya was born on 21 April .

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Answered by amitnrw
0

Given : Ramya told Krishna “12 times the date of my birth added to 31 times the month of my birth is 376”.

To Find :  On which date was Ramya born

Solution:

Date = x   x is integer from 1 to 31

Month = y    y is integer from 1 to 12

12x  + 31y  = 376

=> x =  (376 - 31y) /12

=> x =  31 + ( 4 - 31y)/12

Hence 31y  -  4  = 12k

=>  31y  = 4(3k + 1)

so y = 4  ,  y  =  8   and  y  = 12 are possible values

y  = 4  => k = 10  

y = 8  => k  = 61/3  hence not possible

y = 12 => k  = 92/3  hence not possible

12x  + 31y  = 376

y = 4  => x =   21

Hence 21st April

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