ranbir borrows 20,000 at 12% per annum compound interest. if he repays 8,400 at the end of first year and 9,680 at the end of second year, find the amount of loan outstanding at the beginning of the third year.
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Answered by
28
easy answer
si=20000*12*1/100=2400
amout=20000+2400=22400
22400-8400=14000
si=14000*12*1/100=1680
am=14000+1680=15680
15680-9680=6000
si=6000*12*1/100=720
amout=6720
si=20000*12*1/100=2400
amout=20000+2400=22400
22400-8400=14000
si=14000*12*1/100=1680
am=14000+1680=15680
15680-9680=6000
si=6000*12*1/100=720
amout=6720
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7
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