Ranbir borrows rupees 20000 at 12% per annum compound interest if DPS 8400 at the end of the first test and rupees 9680 at the end of the second year find the amount of loan outstanding at beginning of the third year.
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Step-by-step explanation:
20000×12×1/100=200×12×l
2400_20000 =17600_20000 =2400
2400/100×1×12=288_2400=2112
2112/100×1×12
21.12×12=253.44-2112=1,858.56+20000=21,858.56
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