Question

Ranbir bought a rectangular field of area 24000 square meters and width 120 m. He wants to fence it with two rounds of wire. Find the length of wire that will be required to fence the field. with statement pls

Answer 1

$\large{\underline{\underline{\red{\tt{\purple{\leadsto } GiveN:-}}}}}$

• Ranbir bought a rectangular field of area 24000 square meters.
• Widhth of the field is 120 m .
• He wants to fence it with two rounds of wire.

$\large{\underline{\underline{\red{\tt{\purple{\leadsto } To\:FinD:-}}}}}$

• Length of wire required to fence the field .

$\Large{\underline{\underline{\red{\tt{\purple{\leadsto } AnsweR:-}}}}}$

$\sf \underline{\green{Figure :-}}$

$\setlength{\unitlength}{1 cm}\begin{picture}(12,12)\linethickness{0.4mm}\put(0,0){\line(1,0){5}}</p><p>\put(0,-0.3){ \bf A }\put(5,-0.3){ \bf B } \put(0</p><p>,3.3){ \bf D } \put(5,3.3){ \bf C }\put(5,0){\line(0,1){3}}\put(5,3){\line(-1,0){5}}\put(0,3){\line(0,-1){3}}\put(2.5, -0.3){ \bf 200 m } \put(2.5,3.3){ \bf 200 m } \put(5.2,1.5){ \bf 120 m } \put(-1, 1.5){ \bf 120 m } \end{picture}$

Given that area of the field is 24000 m² .

$\sf \underline{\green{We\:know\:Area\:of\: rectangle \:as. }}$

$\large{\pink{\boxed{\bf Area _{rectangle}=lenght\times Breadth. }}}$

And , the Breadth here is 120 m.

$\tt:\implies Area_{rec.}=(lenght)(breadth)$

$\tt:\implies 24000 m^2 = 120m \times l$

$\tt:\implies l = \dfrac{24000m^2}{120m}$

$\underline{\boxed{\red{\tt:\longmapsto length = 200m}}}$

$\rule{200}2$

$\sf \underline{\green{We\:know\: Perimeter\:of\: rectangle \:as. }}$

$\large{\blue{\boxed{\bf Perimeter _{rectangle}=2(lenght + Breadth) }}}$

$\tt:\implies Perimeter_{rec.}=2(l+b)$

$\tt:\implies Perimeter = 2(200m + 120m)$

$\tt:\implies Perimeter = 2\times 320m$

$\underline{\boxed{\red{\tt:\longmapsto Perimeter = 640m }}}$

Now , since he wants to fence two rounds of wire , hence total required lenght will be

= 2 × 640 m = 1280 m .

Answer 2

Question:

Ranbir bought a rectangular field of area 24000 square meters and width 120 m. He wants to fence it with two rounds of wire. Find the length of wire that will be required to fence the field. ㅤㅤㅤㅤ

Given:

• Area of rectangular field = 24,000m²
• Width of the field = 120m

To find :

• Length of wire required to fence the field.

Solution:

Area of rectangle = length × breadth

$: \implies 24000 = l × 120$

$:\implies l = \frac{24000}{120}$

$: \implies l = 200m^2$

To find the length of wire required to fence the field we need to find the perimeter of the field.

Perimeter of rectangle = 2 ( l + b)

$: \implies 2 ( 200 + 120 )$

$: \implies 2 ( 320)$

Perimeter of the field = 640 m

He need to fence the field twice, so 2 × 640 = 1280 m.

$\rule{200}4$