Question

Ranbir bought a rectangular field of area 24000 square metres and width 120 m. He wants to fence it with two rounds of wire. Find the length of wire that will be required to fence the field.

Answer 1

Given :

• Area of rectangular field = 24000 m².
• Width of rectangular field = 120 m

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To find :

• Length of wire that will be required to fence the field?

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Solution:

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☯ Let length of field be x m.

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$\bf{\dag}\;{\underline{\frak{As\;we\;know\;that,}}}$

$\star\;{\boxed{\sf{\pink{Area_{\;(rectangle)} = length \times breadth}}}}$

$:\implies\sf x \times 120 = 24000$

$:\implies\sf x = \cancel{ \dfrac{24000}{120}}$

$:\implies{\underline{\boxed{\frak{\purple{x = 200\;m}}}}}\;\bigstar$

$\therefore\:{\underline{\sf{Length\:of\;rectangular\;field\:is\: {\textsf{\textbf{200\;m}}}.}}}$

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☯ Now, Finding length of wire that will be required to fence the field.

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• Length of wire required in one round = Perimeter of field

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$\star\;{\boxed{\sf{\pink{Perimeter_{\;(rectangle)} = 2(length + breadth)}}}}$

$:\implies\sf Perimeter_{\;(rectangle)} = 2(200 + 120)$

$:\implies\sf Perimeter_{\;(rectangle)} = 2 \times 320$

$:\implies{\underline{\boxed{\frak{\purple{Perimeter_{\;(rectangle)} = 640\;m}}}}}\;\bigstar$

$\therefore\:{\underline{\sf{Perimeter\:of\;rectangular\;field\:is\: {\textsf{\textbf{640\;m}}}.}}}$

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Therefore,

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• Length of wire required to fence the field in one round = 640 m
• Length of wire required to fence the field in two round = 2 × 640 = 1280 m

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$\therefore\:{\underline{\sf{Hence,\:Total\:Length\:of\;wire\; required\:is\:{\textsf{\textbf{1280\;m}}}.}}}$

Answer 2

Answer:

Given :-

• Ranbir brought a rectangular field of area 24000 m² and width is 120 m. He wants to fence it with two rounds of wire.

To Find :-

• What is the length of wire that will be required of fence the field.

Formula Used :-

$\tt{\boxed{\bold{\small{Area\:<strong> </strong>of\:<strong> </strong>rectangle\:<strong> </strong><strong>=</strong>\:<strong> </strong>Length\:<strong> </strong>\times<strong> </strong>Breadth}}}}$

$\tt{\boxed{\bold{\small{Perimeter\:<strong> </strong>of\:<strong> </strong>rectangle\:<strong> </strong>=\: 2(Length\: +\: Breadth)}}}}$

Solution :-

✰ First, we have to find the length,

Let, the length of the field be x metre

And, the area of the rectangle field is 24000 m² and the breadth is 120 m.

According to the question by using the formula we get,

⇒ 24000 = x × 120

⇒ $\tt\dfrac{\cancel{24000}}{\cancel{120}}$ = x

⇒ 200 = x

➠ x = 200 m

Hence, the length of the rectangle field is 200 m .

✰ Now, we have to find the perimeter,

We get,

• Length = 200 m
• Breadth = 120 m

According to the question by using the formula we get,

↦ Perimeter = 2(200 + 120)

↦ Perimeter = 400 + 240

➦ Perimeter = 640 m

Hence, the perimeter of the rectangle field is 640 m .

Since, we have to find the total length of wire required to fence the field,

★ Length of wire required to fence one round is 640 m

★ And, the length of wire required to fence two rounds is 2 × 640 = 1280 m

$\therefore$ The length of wire that will be required to fence the field is 1280 m .