Chemistry, asked by Nikhil1611, 9 months ago

Ranchi prepared a salt solution with concentration 11.11% (mass by mass percentage)
in 320 g of water. Abhinav prepared a salt solution by dissolving the same amount of salt
(as used by Ranchi), but in 160 g of water. What is the approximate concentration (in
mass by mass percentage) of the solution prepared by Abhinav?​

Answers

Answered by chandnaaashman7
4

Answer:

The question lacks precision, or, more accurately, is confusingly stated.

The question posits a process for preparing a solution, but it says that the salt is dissolved in some solution. You don’t prepare a solution by dissolving a solute in a solution. You do it by dissolving the solute in a solvent.

So what exactly do you mean here?

Have you truly dissolved 11 g of salt in 80 g of something? Which seems to be what you’re saying.

Or have you used 11 g of salt to prepare a solution whose final mass is 80 g? Which is how both of the previous answers have interpreted the question.

There’s a difference, right? Before you, or anyone else, can answer this question, we all have to agree on what the question means.

If your meaning corresponds to #1, then we have 11 g of salt in a total mass of 91 g. Percent is always

Percent=the partthe whole×100  

So if we’re after the percent by mass of the salt (which you don’t exactly say, but which is your likely meaning),

Percent salt=11 g salt91 g total mass×100=12.1  

On the other hand, if your meaning corresponds to #2, then see the two previously posted answers.

Explanation:

HOPE IT HELPS YOUU  

Similar questions