Question

Range 1, 2, 3, 4, 1, 2, 3, 4 ,. . . . . . . . . . . . . . . . . . The sum of the first 2007 posts will be: (A) 5016 (B) 5107 (C) 5020 (D) 5013​

Answer 1

Answer:

(A)

Step-by-step explanation:

There are 2007 numbers to add up. The pattern [1, 2, 3, 4] is repeating, so there are 4 numbers in the sequence. Divide the amount of numbers to add up by the amount of numbers in the sequence to find how many times the sequence repeats.

    2007/4 = 501.75

This means that [1, 2, 3, 4] is repeated 501 times, in full. The 0.75 at the end means that 3 of the 4 numbers are repeated at the end, so [1, 2, 3].

Add the full sequence together: 1 + 2 + 3 + 4 = 10

Then multiply this number by 501, since the pattern repeats 501 full times in 2007.

    10 x 501 = 5010

And then add the last three numbers together: 1 + 2 + 3 = 6

Add this to the value you got before, like so:

    5010 + 6 = 5016

So the answer is (A) 5016