Question

Range of f(x)=1+3cos2x is​

Answer 1

Answer:

the range of f(x) is [-2,4]

Step-by-step explanation:

Let Y = 1 + 3 cos 2x

Now We Know that Cos Function lies

between -1 to 1

So putting These Value We get

Maximum Value = 1 + 3*1 = 4

Minimum Value = 1 + 3*(-1)= -2

So the range of f(x) is [-2,4]

Answer 2

Answer:

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