Math, asked by muneshkumar4848, 5 months ago

range of f(x)=1/4-x^2​

Answers

Answered by Anonymous
1

 \boxed{ \tt{Question :}}

 \tt \pink{→ Range \:  of  \:  \: f(x)= \frac{1}{4}- {x}^{2}}

 \boxed{\tt{Solution :}}

 \tt{→ The  \: Domain  \: is  \: x ∈ (-2  \: and  \: 2)}

 \tt{→ The  \: range \:  is \:  \:   \frac{1}{2} +  \infty }

 \boxed{ \tt{Explanation :}}

 \tt \blue{→ The  \: function \:  is  \: f(x)  = \frac{1}{ \sqrt{4 -  {x}^{2} } }}

 \tt \blue{→ Therefore ,}

 \tt \blue{→4 -  {x}^{2}> 0}

 \tt \blue{→ (2 - x) \:  \: (2 + x) > 0}

 \tt \blue{→ 2 - x > 0}

 \tt \blue{→ 2 + x > 0}

 \tt \blue{→ (x < 2)\: and \: (x >  - 2)}

Note :

Note :→ What'under the “√” sign must be ≥ 0 and we cannot divide by 0.

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