Question

Range of f (x) = x2 + 1 is ​

Answer 1

Answer:

$f(x) = 0 \\ f(x) = {x}^{2} = 0 \\ {x}^{2} + 1 = 0 \\ {x}^{2} = 0 - 1 \\ {x}^{2} = \sqrt{ - 1}$

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Answer 2

Answer:

3

Step-by-step explanation:

x=-1

x=-1-0x=1

x=1×2 +1

x=3