Question

range of first n even natural numbers​

Answer 1

Answer:

Range of the first 'n' natural numbers = n - 1. Range of the last n negative integers = -1-(-n)=n-1. Range of the first 'n' positive even integers = 2n - 2 . Range of first 'n' positive odd integers = (2n + 1) - (1) = 2n -2 .