Question

range of projectile fired at an angle with horizontal is maximum at
a. 0°
b. 90°
c. 45°
d. 180°​

Answer 1

Answer:

$\rm c. \ 45^{\circ}$

Explanation:

Formula of Range of Projectile:

$\boxed{\rm R = \dfrac{u^2 sin 2 \theta}{g}}$

u → Velocity of projection

$\sf \theta$ → Angle of projectile with horizontal

For a given value of u, R is maximum for $\sf sin 2 \theta = 1$ or for $\sf \theta = 45^{\circ}$.

$\boxed{\rm R_{max} = \dfrac{u^2}{g}}$

So, a projectile will go upto the maximum horizontal distance, if it is projected at 45° with the horizontal.