Question

Range of projectile will be minimum when angle of projectile is

Answer 1

range of projectile will be minimum and angle of projectile is 0-90°

Answer 2

Answer:

90°

Explanation:

Tip

• The horizontal displacement of the projectile determines its range. Gravity only acts vertically, hence there is no acceleration in this direction. shows the range line. The range of the projectile, like its time of flight and maximum height, is a function of its initial speed.
• R = v02sin2θ/g
• R= horizontal range (m)
• V0 = initial velocity (m/s)
• g = acceleration due to gravity (9.8m/s2)
• θ = angle of the initial velocity from the horizontal plane (radians or degree)

Find

Minimum Angle of projectile

Solution

$\mathrm{R}=\frac{\mathrm{u}^{2} \sin 2 \theta}{\mathrm{g}}$

Minimum value of range can be zero.

$\therefore \mathrm{R}=0 \text { at } 2 \theta=0$

or $2 \theta=180^{\circ}$

So,$\theta=0$

or$\theta=90^{\circ}$

Final Answer

Minimum angle of projectile is$\theta=90^{\circ}$

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