Question

range of real function f(x)=3sin x-2​

Answer 1

Answer:

3 sinx-2 is the correct answer for this

Answer 2

Answer:

Given that it is a real function so x € R.

Hence, range of sin x is

[-1,1].

so we can calculate the range of f(x) by satisfying all the given conditions of the function as shown below:-

$as \\ - 1 \leqslant sinx \leqslant 1 \\ multiply \: all \: sides \: by \: 3 \\ - 3 \leqslant 3sinx \leqslant 3 \\ now \: subtract \: 2 \: from \: all \: \: sides \\ - 5 \leqslant 3sinx \leqslant 1 \\ \implies \: - 5 \leqslant f(x) \leqslant 1</p><p> \:$

from this range of f(x) is :-

[-5,1]..(Answer)