Math, asked by charantej40, 1 year ago

Range of sin "'x-cos" x is​

Answers

Answered by MissTanya
1

\huge\underline\purple{ANSWER :-}

cosx ranges from −1 to 1, and sinx is increasing on (−π2,π2), so since [−1,1]⊂(−π2,π2) the minimum and maximum are sin(−1) and sin(1), respectively.

Answered by Anonymous
0

cosx ranges from −1 to 1, and sinx also -1 to 1

Similar questions