Question

range of sinx+1 in function
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Answer 1

Answer:

As, we know that

∣sin−1∣sinx∣∣=cos−1∣cosx∣,∀xϵ domain

∴f(x)=∣sin−1∣sinx∣∣−cos−1∣cosx∣=0,∀x∈ domain

∴ Range of f(x)∈{0}

Hence, (a) is the correct answer.