range of the f(x)=e^x-1/e^x+1
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Answered by
1
Answer:
f(x)=
e
x
−1
e
x
+1
∴n(d)=f
As e
x
−1=0
∴e
x
=1
∴
x=0
∴ for x=0 function is not variable
Also, Let f(4)=1
e
x
−1
e
x
+1
=1
e
x
+1=e
x
−1
∴1=−1
Not possible
∴n(d)=1
n(r)=1
∴n(d)+n(r)=2
Step-by-step explanation:
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