Question

Range of the f(x)
(e^x - 1)/(e^x+ 1)
​

Answer 1

Answer:

(-1, 1)

Step-by-step explanation:

for x = 0, numerator becomes 0

1) for a any positive value of n

numerator is 2 less than denominator,

therefore fraction is always lesser than 1.

2) for a negative value of n

numerator becomes (1/eⁿ -1) which is a negative value but denominator remains positive, so values of f(x) is negative, for a greater values of x like -∞ values will be closer to -1.

therefore range is (-1, 1)