Math, asked by pujarsharnappa1971, 9 months ago

Rani brought to cell phones for rupees 24,00 she sold one cell phone at 10% loss and another for 15% profit find SP of two cell phones and also find lost or profit​

Answers

Answered by arjunsahu1
1

Answer

Cost of 2 phones = 2400

so cost of 1 phone = 2400/2 = 1200

now,

first phone

cost price = 1200

loss = 10% of 1200 = 120

selling price = 1200 - 120 = 1080

second phone ,

cost price = 1200

profit = 15% of 1200= 180

selling price = 1200+180 = 1380

so total cost price = 2400

total selling price = 1080 + 1380 = 2460

so profit = 2460-2400=60

Answered by drishtiverma59
1

Answer:

total cost price(CP) of 2 phones= 2400

=> CP of 1 phone = 1200

LOSS

CP we know=1200

loss percentage= 10%

loss=10/100 ×1200

=120

Selling price of phone= CP- loss

= 1200-120

=1080

PROFIT

CP we know=1200

profit percentage=15%

profit=15/100×1200

=180

selling price of phone=CP+ profit

=1200+180

=1380

total selling price= 1080+1380= 2460.

since, SP>CP,

PROFIT

profit= SP-CP

=2460-2400

=60

therefore, Rani earned a profit of Rs.60.

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