Rani has three tops, two pairs of jeans and two pairs of shoes. Totally, in how many different ways can she choose and combine one top, one pair of jeans and one pair of shoes to wear for a party? (For example: one possible way would be to combine the white top, blue jeans and brown shoes)
6
7
12
25
Answers
Answer:
12 different ways Rani can choose and combine one top, one pair of jeans and one pair of shoes to wear for a party
Step-by-step explanation:
- Rani has 3 tops, 2 pairs of jeans and 2 pairs of shoes.
- 3 tops, each top can be worn with each pair of jeans. Total number of jeans is 2 pair. This is 3×2=6ways
- Rani has 2 pairs of shows and each pair can be worn with each of the 6 outfits.
- So , total number of combination of the outfit = 6×2=12
Answer: 12 different ways Rani can choose and combine one top, one pair of jeans, and one pair of shoes to wear for a party.
Step-by-step explanation:
Rani has three tops, two pairs of jeans, and two pairs of shoes.
Totally, she chooses and combines one top, one pair of jeans, and one pair of shoes to wear for a party.
First, let us see in how many ways she can combine the jeans and tops. She could wear the red top with the blue or brown jeans, giving 2 combinations. Similarly, she could wear the white top with either of the jeans, giving 2 more combinations. We also get 2 such combinations with the blue top. So we have 6 different combinations of jeans and tops. Now she can wear each of these combinations with black shoes or brown shoes. So we have 6 × 2 = 12 combinations in all.
Hence, the total number of combinations of the outfit = 12.
#SPJ2