Question

Rani is twice as old as vani.If four years are added to rani's age and six years are subtracted from vani's age.Rani's age will be four times vani's age.what are their ages?

Answer 1

$\underline{\textbf{Question}}$

Rani is twice as old as vani.If four years are added to rani's age and six years are subtracted from vani's age.Rani's age will be four times vani's age.what are their ages?

$\underline{\textbf{Answer}}$

In present

Let Vani Age=x years

Then Rani Age=2x years

If 4 years added to Rani's Age

Rani Age now=(2x+4) years

If 6 is Subtract from Vani's Age

Vani's Age now=(x-6) years

Rani Age Is also 4×(x-6)

A/Q

4(x-6)=2x+4

4x-24=2x+4

4x-2x=4+24

2x=28

x=$\frac{28}{2}$

x=14

Vani Age now=x years=14 years

Rani Age now=2x=2×14=28 years



CHeck

4(x-6)=2x+4

4×14-24=2×14+4

56-24=28+4

32=32

Hence It is Right

$\boxed{\mathtt{\huge{Vani=14\:years}}}$

$\boxed{\mathtt{\huge{Rani=28\:years}}}$

Answer 2

Answer:

Vani's age is 14 years

Rani's age is 28 years

Step-by-step explanation:

Let rani's age be = 2X

Let vani's age be = X

According to the question

(2X+4) = 4(X-6)

2X + 4 =  4X - 24

2X - 4X = -24 - 4

-2X = - 28

2X = 28

X = 28/2

X = 14

Vani's age is 14 years

Rani's age = 2X

Rani's age = 14 × 2

Rani's age = 28 years

Verify

(2×14+4) = 4(14-6)

(28+4) = (56-24)

(32)=(32)

Hence verified