Question

Rani purchased 5 cows and 2 horses for Rs.66000. When she sells the cows at 15% profit

and the horses at 10% profit, she earns a total profit of Rs.9100. What is the difference

between the cost price of one cow and that of one horse?
​

Answer 1

Answer:

2000 rs

Step-by-step explanation:

let c.p of cow(100%) =x

c.p of horse (100%)= y

500x+200y=66000

50x+20y=6600......eqn 1

10% profit of horse and 15% of cows= 75x+20y=9100..eqn2

solve eqn 1 and 2

x=100rs

substitute x value in eqn 1

50000+200y=66000

200y=66000-50000

200y=16000

y=80

so each cow c.p= 100%x= 10,000rs,

and each horse c.p= 100%y= 8000

difference between c.p= 10,000-8000=2,000rs

hope you understand

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Answer 2

Given :- Rani purchased 5 cows and 2 horses for Rs.66000. When she sells the cows at 15% profit and the horses at 10% profit, she earns a total profit of Rs.9100. What is the difference between the cost price of one cow and that of one horse ?

Solution :-

Let us assume that, CP of 1 cow is Rsx and CP of 1 horse is Rs.y .

Than,

→ Total CP of 5 cow + 2 horse = Rs.66000

→ 5x + 2y = 66000 ---------- Eqn.(1)

Also, given that,

• Profit % on cow = 15% .
• Profit % on horse = 10% .
• Total profit = Rs.9100 .

So,

→ 15% of 5x + 10% of 2y = 9100

→ (15 * 5x)/100 + (10 * 2y)/100 = 9100

→ 75x + 20y = 910000

→ 5(15x + 4y) = 910000

→ 15x + 4y = 182000 --------- Eqn.(2)

Now, Multiply Eqn.(1) by 3 and than subtract Eqn.(2) from the result , we get,

→ 3(5x + 2y) - (15x + 4y) = 3*66000 - 182000

→ 15x - 15x + 6y - 4y = 198000 - 182000

→ 2y = 16000

→ y = Rs.8000 .

Putting value of y in Eqn.(1) now,

→ 5x + 2 * 8000 = 66000

→ 5x + 16000 = 66000

→ 5x = 66000 - 16000

→ 5x = 50000

→ x = Rs.10000

Therefore,

→ x - y = 10000 - 8000 = Rs.2000 (Ans.)

Hence, the difference between the cost price of one cow and that of one horse is Rs.2000 .

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