Rani took 30 minutes to cycle from school to her home at an average speed of 12 km/h. If she wanted to reach home 10 minutes early, what must her average speed be?
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we know that distance = speed *time
given, t=30 min i.e,1/2 hrs and velocity = 12km/hr
thrfre distance=6kms.
now given that the time is reduced by 10min. ie the time taken should be 20 min.
bt the distance remains the same.
therefore velocity=distance/time
and it equals to 6kms/(1/3)hrs =18kms/hr.
given, t=30 min i.e,1/2 hrs and velocity = 12km/hr
thrfre distance=6kms.
now given that the time is reduced by 10min. ie the time taken should be 20 min.
bt the distance remains the same.
therefore velocity=distance/time
and it equals to 6kms/(1/3)hrs =18kms/hr.
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