Ranika wanted her friend Radhika's mobile number,but Radhika played a trick.She gave her the number as- 9 x y z p 1 q 2 r 3 and told her to decode it with the help of following equations;
a)3x=2x+9
b)6y-7/3y+9=1/3
c)8z-8=6z+8
d)p+3/10 p=13/10
e)4(q+4)=5(q+2)
f)3(r+10)+200=236
Answers
Given : number 9 x y z p 1 q 2 r 3
Equations :
a)3x=2x+9
b)6y-7/3y+9=1/3
c)8z-8=6z+8
d)p+3/10 p=13/10
e)4(q+4)=5(q+2)
f)3(r+10)+200=236
To Find : The Number
Solution:
a)3x=2x+9 => x = 9
b)6y-7/3y+9=1/3 => 18y - 21 = 3y + 9 => 15y = 30 => y = 2
c)8z-8=6z+8 => 2z = 16 => z = 8
d)p+3/10 p=13/10 => 13p/10 = 13/10 => p = 1
e)4(q+4)=5(q+2) => 4q + 16 = 5q + 10 => 6 = q
f)3(r+10)+200=236 => 3r + 30 + 200 = 236 => 3r = 6 => r = 2
9 x y z p 1 q 2 r 3
x = 9 , y = 2 , z = 8 , p = 1 , q = 6 and r = 2
9928116223 is the number
Learn More:
Solve the following x+y/xy=5 and x-5/xy=7 - Brainly.in
brainly.in/question/8168066
solve for x and y : x+y/xy=2,xy/=6
brainly.in/question/12892518
Answer:
a)3x=2x+9 => x = 9
b)6y-7/3y+9=1/3 => 18y-21-3y + 9 => 15y = 30 => y = 2
c)8z-8=6z+8 => 2z = 16 => z= 8
d)p+3/10 p=13/10 => 13p/10 = 13/10 => p = 1
e)4(q+4)=5(q+2) => 4q + 16 = 5q + 10 => 6 = q
f)3(r+10)+200-236 => 3r+ 30 + 200 = 236 =>
3r = 6=>r = 2
9xyzp1q2r3
x = 9, y = 2, z = 8, p=1, q = 6 and r = 2
9928116223 is the number.