Question

Ranika wanted her friend Radhika's mobile number,but Radhika played a trick.She gave her the number as- 9 x y z p 1 q 2 r 3 and told her to decode it with the help of following equations;
a)3x=2x+9
b)6y-7/3y+9=1/3
c)8z-8=6z+8
d)p+3/10 p=13/10
e)4(q+4)=5(q+2)
f)3(r+10)+200=236​

Answer 1

Given :  number  9 x y z p 1 q 2 r 3

Equations :

a)3x=2x+9

b)6y-7/3y+9=1/3

c)8z-8=6z+8

d)p+3/10 p=13/10

e)4(q+4)=5(q+2)

f)3(r+10)+200=236​

To Find : The Number

Solution:

a)3x=2x+9    => x = 9  

b)6y-7/3y+9=1/3   => 18y - 21 = 3y + 9  => 15y  = 30  => y = 2

c)8z-8=6z+8   => 2z = 16  => z = 8

d)p+3/10 p=13/10   => 13p/10  = 13/10 => p = 1

e)4(q+4)=5(q+2)  => 4q + 16 = 5q  + 10  => 6 = q

f)3(r+10)+200=236​ => 3r + 30 + 200 = 236  => 3r   = 6 => r  = 2

9 x y z p 1 q 2 r 3

x = 9  , y = 2 , z = 8  , p = 1 , q  = 6  and  r = 2

9928116223 is the number

Learn More:

Solve the following x+y/xy=5 and x-5/xy=7 - Brainly.in

brainly.in/question/8168066

solve for x and y : x+y/xy=2,xy/=6

brainly.in/question/12892518

Answer 2

Answer:

a)3x=2x+9 => x = 9

b)6y-7/3y+9=1/3 => 18y-21-3y + 9 => 15y = 30 => y = 2

c)8z-8=6z+8 => 2z = 16 => z= 8

d)p+3/10 p=13/10 => 13p/10 = 13/10 => p = 1

e)4(q+4)=5(q+2) => 4q + 16 = 5q + 10 => 6 = q

f)3(r+10)+200-236 => 3r+ 30 + 200 = 236 =>

3r = 6=>r = 2

9xyzp1q2r3

x = 9, y = 2, z = 8, p=1, q = 6 and r = 2

9928116223 is the number.