Math, asked by BansriShah4842, 1 year ago

Ranjan bought a second hand scooter for Rs 6000 he spent Rs 300 on its repair and sold at to vineet at a profit of 10%. Vineet sold the scooter to Mukesh at a loss of 10%. At what price did Mukesh buy the scooter

Answers

Answered by ushasharmamint
334

Answer:

Step-by-step explanation:

(Ranjan) CP of the scooter = ₹6000

Overhead expenses = ₹300

Actual CP = ₹6300

Profit% = 10%

Profit = 10% of ₹6300

= 10/100*6300

= ₹630

SP = CP + Profit

= ₹6300 + ₹630

= ₹6930

(Vineet) CP of the scooter = ₹6930

Loss% = 10%

Loss = 10% of ₹6930

= 10/100*6930

= ₹ 693

SP = CP - Loss

= ₹6930 - ₹693

= ₹6237

Mukesh buy the scooter at ₹6237

Answered by kumarrakesh047090
65

Answer:

Mukesh Bought Scooter at RS.6237

Step-by-step explanation:

C.P of Scooter bought by Ranjan = Rs.6000

Money spent on Repairing = Rs.300

Actual C.P = 6000+300

                  = R.s. 6300

Profit on Selling = 10 %

S.P (C.P of Vineet)= (100+Gain%)/100*C.P.

                              = (100+10)100*6300

                              = 110/100*6300

                              = Rs.6930

C.P of Scooter bought by Vineet = Rs.6930

Loss = 10%

S,P.(C.P. Of Mukesh) =  (100-Loss%)/100*C.P.

                                  =  (100-10)/100*6930

                                  = 90/100*6930

                                  = Rs.6237

So, Mukesh bought the Scooter at RS.6237

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