Question

Ranjan brought a tv set for ₹54,000. He paid 1/9 of the price in cash and the rest in 24 monthly installments. What is the amount he had to pay every month?
Plz make the answer₹2000​

Answer 1

Cost of a TV set Ranjan bought = ₹ 54,000

Money he paid as cash for the TV set :-

$= \frac{\texttt{1}}{\texttt{9}} \: \texttt{ of \: the \: price}$

$= \frac{\texttt{1}}{\texttt{9}} \texttt{ \: of \: 54000}$

$= \frac{\texttt{1}}{\texttt{9}} \texttt{ \: × \: 54000}$

$= \frac{\texttt{1×54000}}{\texttt{9} }$

$= \frac{\texttt{54000}}{\texttt{9} }$

$=\texttt{₹\color{hotpink}6000}$

Money Ranjan payed as cash = ₹6000

Money Ranjan would have paid in installments :-

$= \texttt{54000 - 6000}$

$=\texttt{ ₹\color{hotpink}48000}$

Money Ranjan would have payed in installments = ₹48,000

Number of months in which Ranjan payed in installments = 24

Money he would have to pay each month :-

$= \frac{\texttt{48000}}{\texttt{24} }$

$= {{\bold{₹\color{hotpink} 2000}}}$

Therefore, Money Ranjan had to pay each month = ₹2000

Answer 2

$\mathtt{\Huge{\color{indigo}{A}{\color{blue}{N}{\color{green}{S}{\color{violet}{W}{\color{orange}{E}{\color{red}{R}}}}}}}}$

$\LARGE \color{indigo}{\mathtt{Given: - }}$

• Total amount = ₹54,000
• Price paid by him = 1/9 of total.
• Rest of money in 24 monthly installments

$\LARGE \color{limegreen}{\mathtt{To \: \: find }}$

• Amount he had to pay every month

So, according to the question:-

$</p><p> \large{ \color{orange}{ \mathtt{Total \: \: amount \: \: of \: \: the \: \: refrigerator = Rs \: 54,000}}}$

Amount paid in cash = 1/9 of Rs. 5000

$\\ \mathtt{= \frac{1}{9} × 54,000}$

$\color{green} \large = \underbrace{ \mathtt{Rs. 6000}}$

Balance amount :-

$\\ \mathtt{= Rs \: \: 54,000 \: \: – \: \: Rs \: \: 6000}$

$\color{green} \large = \underbrace{ \mathtt{ Rs. 48000}}$

∴ Amount of each installment :-

$\Large{\mathtt{ \implies \: Rs. 48000 ÷ 24}}$

$\Large{\boxed{\boxed{ \color{red}{\mathtt{ \implies \: Rs \: 2000}}}}}$

Therefore, he has to pay 2000 every month.