Ranjeet calculated mean of six observations as 42 . Later on, he found that he misread 42 as 24 and 27 as 72. What is the correct mean of the observations..?
(a) 36.8
(b) 37.5
(c) 37.6
(d) 42.5
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Answers
Question :-
Ranjeet Calculated the Mean of 06 Observations as 42. Later on, He found that He Misread 42 as 24 and 27 as 72. What is the correct Mean of the Observations?
(a) 36.8
(b) 37.5
(c) 37.6
(d) 42.5
Solution :-
The Calculated Mean of 6 Observations = 42
∴ The Calculated Sum of these Observations =
-
The Correct Sum of these Numbers =
∴ The Correct Mean of these Observations =
⇒
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Step-by-step explanation:
Question :-
Ranjeet Calculated the Mean of 06 Observations as 42. Later on, He found that He Misread 42 as 24 and 27 as 72. What is the correct Mean of the Observations?
(a) 36.8
(b) 37.5
(c) 37.6
(d) 42.5
Solution :-
The Calculated Mean of 6 Observations = 42
∴ The Calculated Sum of these Observations = 42 \times 6 = \bold {252}42×6=252
-
The Correct Sum of these Numbers =
\boxed {\bold {[252 - (Wrong\: Number) + (Correct\: Number)]}}
[252−(WrongNumber)+(CorrectNumber)]
\begin{gathered}\begin {aligned} & \implies [252 - (24 + 72) + (42 + 27)] = [252 - 96 + 69]\\\\& = \bold {225} \end {aligned}\end{gathered}
⟹[252−(24+72)+(42+27)]=[252−96+69]
=225
∴ The Correct Mean of these Observations = \frac{225}{6} = \bold {37.5}
6
225
=37.5
⇒ \mathfrak {\red {Option\: B - 37.5}\: is\: the\: Right\: Answer...}OptionB−37.5istheRightAnswer...
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