Ranjeet makes a deposit of rs. 50,000 in the punjab national bank for a period of 2 y2 years. if the rate of interest is 12% per annum compounded half-yearly, find the maturity value of the money deposited by him.
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The amount is Rs. 63123.848
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Answer:66,911.27
Explanation:
p= 50,000
t= 2.5 months = 6 months of 5
r= 12% but it half yearly so it come 6%
we know CI %= X+Y+XY/100
for first two 6 month CI % will come = 6+6+6*6/100=12.36
then next 6 month CI % =12.36+6+12.36*6/100= 19.10
then next 6 month CI % = 19.10+6+19.10*6/100=26.24
for last 6 month CI% = 26.24+6+26.24*6/100= 33.82
interest = p*33.82/100= 50000*33.82/100= 16,911.27
amount = 16,911.27+50,000= 16,911.27
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