Question

Rank of an invertible matrix of order n is​

Answer 1

Since invertible means one-to-one and onto, we have to prove that. ... rank(A)=n means dim(N(A))=0 which means one-to-one.

Answer 2

Answer:

Since invertible means one-to-one and onto, we have to prove that. ... rank(A)=n means dim(N(A))=0 which means one-to-one.